10th Class Science Electricity and Circuits Question Bank Electricity

  • question_answer
    In an electrolysis experiment a current C passes through two different cells in series, one containing a solution of copper sulphate and the other a solution of silver nitrate. The ratio of increase of the weights at cathode in the two cells will be

    A)  in the ratio of the atomic weights of copper and silver

    B)  in the ratio of the density of copper and silver

    C)  in the ratio of half the atomic weight of copper to the atomic weight of silver  

    D)  in the ratio of half the atomic weight of copper to half the atomic weight of silver

    Correct Answer: C

    Solution :

     Being in series, \[Q\] is equal to same \[\therefore \]\[m\propto W\propto \]atomic weight / valency So,\[\frac{{{m}_{cu}}}{{{m}_{Ag}}}=\frac{atomic\,\,weight\,\,of\,\,Cu}{atomic\,\,weight\,\,of\,\,Ag}\times \frac{valency\,\,of\,\,Ag}{valency\,\,of\,\,Cu}\]             \[=\frac{1}{2}\times \frac{atomic\,\,weight\,\,of\,Cu}{atomic\,\,weight\,\,of\,\,Ag}\]


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