A) \[-2abc\]
B) \[abc\]
C) 0
D) \[{{a}^{2}}+{{b}^{2}}+{{c}^{2}}\]
Correct Answer: C
Solution :
\[\left| \,\begin{matrix} 0 & a & -b \\ -a & 0 & c \\ b & -c & 0 \\ \end{matrix}\, \right|\] = 0 (Since value of determinant of skew-symmetric matrix of odd orders is 0).
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