A) 2
B) 4
C) 0
D) 1
Correct Answer: C
Solution :
Given, \[\Delta =\left| \,\begin{matrix} 41 & 42 & 43 \\ 44 & 45 & 46 \\ 47 & 48 & 49 \\ \end{matrix}\, \right|.\] Applying \[{{C}_{2}}\to {{C}_{2}}-{{C}_{1}},\,{{C}_{3}}\to {{C}_{3}}-{{C}_{2}}\] we get\[\Delta =\left| \,\begin{matrix} 41 & 1 & 1 \\ 44 & 1 & 1 \\ 47 & 1 & 1 \\ \end{matrix}\, \right|\]. Since two columns (\[{{C}_{2}}\] and\[{{C}_{3}}\]) are identical, therefore\[\Delta =0\].
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