A) \[{{e}^{-1}}\]
B) \[e\]
C) \[\frac{e+{{e}^{-1}}}{2}\]
D) \[\frac{e-{{e}^{-1}}}{2}\]
Correct Answer: D
Solution :
\[1+\frac{1}{3\ !}+\frac{1}{5\ !}+\frac{1}{7\ !}+......\infty =\frac{e-{{e}^{-1}}}{2}\].
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