JEE Main & Advanced Mathematics Sequence & Series Question Bank Exponential series

  • question_answer
    In  the expansion of  \[\frac{a+bx}{{{e}^{x}}}\],  the coefficient of \[{{x}^{r}}\] is

    A) \[\frac{a-b}{r\,!}\]

    B)   \[\frac{a-br}{r\,!}\]

    C) \[{{(-1)}^{r}}\frac{a-br}{r\,!}\]

    D) None of these

    Correct Answer: C

    Solution :

    \[(a+bx){{e}^{-x}}\] \[=(a+bx)\left\{ 1-\frac{x}{1\ !}+\frac{{{x}^{2}}}{2\ !}-\frac{{{x}^{3}}}{3\ !}+.......+{{(-1)}^{n}}\frac{{{x}^{n}}}{n\ !}+...... \right\}\]    The coefficient of\[{{x}^{r}}\]\[=a\frac{{{(-1)}^{r}}}{r\ !}+b\frac{{{(-1)}^{r-1}}}{(r-1)\ !}=\frac{{{(-1)}^{r}}}{r\ !}(a-br)\].


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