A) \[\left( 1+\frac{{{m}_{1}}}{{{m}_{2}}} \right)\sqrt{gh}\]
B) \[\frac{{{m}_{1}}}{{{m}_{2}}}\sqrt{2gh}\]
C) \[\left( 1+\frac{{{m}_{1}}}{{{m}_{2}}} \right)\sqrt{2gh}\]
D) \[\left( 1+\frac{{{m}_{2}}}{{{m}_{1}}} \right)\sqrt{2gh}\]
Correct Answer: D
Solution :
Final velocity of bullet and the block\[=\sqrt{2gh}\] If initial velocity of the bullet is\[u\], then \[{{m}_{1}}u+0=({{m}_{1}}+{{m}_{2}})\sqrt{2gh}\] \[\Rightarrow \] \[u=\left( 1+\frac{{{m}_{2}}}{{{m}_{1}}} \right)\sqrt{2gh}\]
You need to login to perform this action.
You will be redirected in
3 sec
