A) \[\text{2}.\text{4 x 1}{{0}^{\text{5}}}\text{ m}/\text{sec}\]
B) \[0.\text{24 x 1}{{0}^{\text{5}}}\text{ m}/\text{sec}\]
C) \[\text{24 x 1}{{0}^{\text{5}}}\text{ m}/\text{sec}\]
D) \[\text{245 x 1}{{0}^{\text{5}}}\text{ m}/\text{sec}\]
Correct Answer: A
Solution :
Mass of alpha particle\[=4\] Mass of remaining nucleus\[=234\] Recoil speed of the heavier particle will be smaller. \[\therefore \] \[v'=1.5\times {{10}^{7}}\times \frac{4}{234}\] \[=2.4\times {{10}^{5}}m/s\]
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