A) 0.76 m
B) 10 m
C) 10.3 m
D) 11 m
Correct Answer: C
Solution :
\[{{h}_{mercury}}=76cm\] \[{{h}_{water}}=?\] \[{{d}_{mercury}}=13.6gc{{m}^{3}}\] \[{{d}_{water}}=1gc{{m}^{3}}\] \[{{g}_{mercury}}=g\] \[{{g}_{water}}=g\] We know that \[P=hdg\] But \[{{P}_{mercury}}={{P}_{water}}\] \[\Rightarrow \] \[{{h}_{mercury}}\times {{d}_{mercury}}\times g={{h}_{water}}\times {{d}_{water}}\times g\] \[\Rightarrow \] \[{{h}_{water}}=\frac{76\times 13.6}{1}=1033.6\,cm=10.34\,m\] The correct answer is C.
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