A) 0
B) e
C) 1/e
D) None of these
Correct Answer: D
Solution :
We have \[{{e}^{{{\log }_{10}}\tan \,\,{{1}^{o}}+{{\log }_{10}}\tan \,\,{{2}^{o}}+{{\log }_{10}}\,\tan \,\,{{3}^{o}}+..........+{{\log }_{10}}\,\tan \,\,{{89}^{o}}}}\] \[={{e}^{{{\log }_{10}}\,(\tan \,\,{{1}^{o}}\,\tan \,\,{{2}^{o}}\,\,\tan \,\,{{3}^{o}}.....\tan \,\,{{89}^{o}})}}={{e}^{{{\log }_{10}}\,\,1}}={{e}^{o}}=1\]
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