A) 2.35 hours
B) 23.5 hours
C) 3.25 hours
D) 32.5 hours
Correct Answer: A
Solution :
Orbital velocity,\[{{v}_{0}}=\sqrt{\frac{G{{M}_{e}}}{{{R}_{e}}+h}}\] \[=\sqrt{\frac{(6.67\times {{10}^{-11}})(6\times {{10}^{24}})}{6380+2620}}\] \[=\mathbf{6}\mathbf{.67}\,\,\mathbf{km/sec}\] Time-period of revolution, \[T=2\pi \frac{({{R}_{e}}+h)}{{{v}_{0}}}\] \[=\frac{2\times 3.14\times (6380+2620)}{6.67\times {{10}^{3}}}\] \[\mathbf{=8474}\,\,\mathbf{sec=2}\mathbf{.35}\]hours
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