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JEE Main & Advanced Chemistry Coordination Chemistry Question Bank Hybridisation and Geometry

  • question_answer
    The shape of \[{{\left[ Cu{{\left( N{{H}_{3}} \right)}_{4}} \right]}^{2+}}\] is square planar, \[C{{u}^{2+}}\] in this complex is [NCERT 1989; RPET 1999]

    A) \[s{{p}^{3}}\] hybridised

    B) \[ds{{p}^{2}}\]hybridised

    C) \[s{{p}^{3}}d\] hybridised

    D) \[s{{p}^{3}}{{d}^{2}}\] hybridized

    Correct Answer: B

    Solution :

    Due to formation of inner orbital complex.


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