question_answer

The volume of vessel A is twice the volume of another vessel B, and both of them are filled with the same gas. If the gas in A is at twice the temperature and twice the pressure in comparison to the gas in B, what is the ratio of the gas molecules in A and B?

Answer:

                As           \[PV=nRT\] \[\therefore \]  \[{{n}_{B}}=\frac{PV}{RT}\]and \[{{n}_{A}}=\frac{2P.2V}{R.2T}=2\frac{PV}{RT}\]and \[{{n}_{A}}:{{n}_{B}}=\mathbf{2:1}\]