| \[X+YS{{O}_{4}}\to Y+XS{{O}_{4}}\] |
A) \[Al,Mg\]
B) \[Zn,Cu\]
C) \[Ag,K\]
D) \[H,Al\]
Correct Answer: B
Solution :
\[Zn+CuS{{O}_{4}}\to Cu+ZnS{{O}_{4}}.\] Hence, X is zinc and Y is copper.
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