A) 5 notes of Rs.100, 1 notes of Rs.20, 2 notes of Rs.10, 4 coins of Rs. 1, 3 coins of 50p & 4 coins of 25p.
B) 4 notes of Rs.100.4 notes of Rs.20. 2 notes of Rs.10, 10 coins of Rs. 1, 20 coins of 50p & 10 coins of 25p.
C) 4 notes of Rs.100, 5 notes of Rs.20, 4 notes of Rs.10. 2 coins of Rs. 1. 3 coins of 50p & 4 coins of 25p.
D) 5 notes of Rs.100, 1 notes of Rs.20, 2 notes of Rs.10. 3 coins of Rs. 1, 2 coins of 50p & 4 coins of 25p.
Correct Answer: D
Solution :
Let's check all option one by one In Option , 5 notes of Rs.100, 1 notes of Rs.20, 2 notes of Rs.10, 4 coins of Re 1, 3 coins of 50p & 4 coins of 25p Total amount=5\[\times \]Rs.100 + 1\[\times \]Rs.20 + 2\[\times \]Rs.10 + 4\[\times \]Rs.1 + 3\[\times \]Rs.0.50 * 4\[\times \]Rs.0.25 = Rs.500 + Rs.20 + Rs.20 + Rs.4 + Rs.1.50 + Rs.1 = Rs.526.50, this not right combination. In option , 4 notes of Rs.100, 4 notes of Rs.20, 2 notes of Rs.10, 10 coins of Re 1, 20 coins of 50p & 10 coins of 25p Total amount = 4\[\times \]Rs.100+4\[\times \]Rs.20+2\[\times \]Rs.10 + 10\[\times \]Rs.1+ 20\[\times \]Rs.0.5 + 10\[\times \]Rs.0.25 = Rs.400 + Rs.80 + Rs.20 + Rs.10 + Rs.10 + Rs.2.50 = Rs.522.50, this is not right combination. In option , 4 notes of Rs.100, 5 notes of Rs.20, 4 notes of Rs.10, 2 coins of Re 1, 3 coins of 50p & 4 coins of 25p. Total amount = 4\[\times \]Rs.100+5\[\times \]Rs.20 + 4\[\times \]Rs.10 + 2\[\times \]Rs.1+3\[\times \]Rs.0.50 + 4\[\times \]Rs.0.25 = Rs.400 + Rs.100 + Rs.40 + Rs.2 + Rs.1.50 + Rs.1 = Rs.544.50, this not right combination. In option , 5 notes of Rs.100, 1 notes of Rs.20, 2 notes of Rs.10, 3 coins of Re 1, 2 coins of 50p <& 4 coins of 25p. Total amount =5\[\times \]Rs.100 + 1\[\times \]Rs.20 + 2\[\times \]Rs.10 + 3\[\times \]Rs.1 + 2\[\times \]Rs.0.50 + 4\[\times \]Rs.0.25 = Rs.500 + Rs.20 + Rs.20 + Rs.3 + Re 1 + Re 1 = Rs.545, this is right combination. Hence with option, Shikhar can buy the birthday present.
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