9th Class Science Time and Motion Question Bank Motion

  • question_answer
    The coordinates of moving particle at any time t are given by\[x=a{{t}^{2}}\] and\[\text{y }=\text{ b}{{\text{t}}^{\text{2}}}\]. The speed of the particle is

    A)  \[2t(a+b)\]

    B)  \[2t\sqrt{{{a}^{2}}+{{b}^{2}}}\]  

    C)  \[2t\left( \sqrt{{{a}^{2}}-{{b}^{2}}} \right)-2t\left( \sqrt{{{a}^{2}}-{{b}^{2}}} \right)\]

    D)  \[\sqrt{{{a}^{2}}+{{b}^{2}}}\]

    Correct Answer: B

    Solution :

     \[r=\hat{i}x+\hat{j}y\]                \[=\hat{i}a{{t}^{2}}+\hat{j}b{{t}^{2}}\]             \[v=\frac{dr}{dt}=\hat{i}2at+\hat{j}2bt\] Magnitude of \[\vec{v}=\sqrt{4{{a}^{2}}{{t}^{2}}+4{{b}^{2}}{{t}^{2}}}\]             \[=2t\sqrt{{{a}^{2}}+{{b}^{2}}}\]


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