A) \[{{x}^{2}}-4x-12\]
B) \[{{x}^{2}}+4x+12\]
C) \[{{p}^{2}}+6p-4\]
D) \[{{x}^{2}}-5x+6\]
Correct Answer: C
Solution :
Given sum of the zeros = (- 5) and product of the zeros = 6 \[\text{6}0={{\text{2}}^{\text{2}}}\times \text{3}\times \text{5}\]Polynomial \[\therefore \] \[={{2}^{2}}\times 3\times 5\times 2=120\] \[f(p)={{\text{p}}^{\text{3}}}+\text{6}{{\text{p}}^{\text{2}}}+\text{lip}+\text{6}\] \[f(p)\] \[p(x)={{x}^{2}}+3x-2\] Hence, the polynomial is \[\Rightarrow \].
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