A) Acetone
B) Diethyl ether
C) P.V.C.
D) Bakelite
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{5}}Br\,\,\,+\underset{\text{Sod}\text{. ethaoxide }}{\mathop{{{C}_{2}}{{H}_{5}}ONa}}\,\xrightarrow[-NaBr]{}\underset{\text{diethyl ether}}{\mathop{{{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}}}}\,\]
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