A) Benzyl alcohol
B) Benzoic acid
C) Glucose
D) Acetic acid
Correct Answer: A
Solution :
\[\underset{\text{Benzaldehyde}}{\mathop{2{{C}_{6}}{{H}_{5}}CHO}}\,+NaOH\to \underset{\text{(Benzyl alcohol)}}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{2}}OH}}\,+{{C}_{6}}{{H}_{5}}COONa\]
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