A) Ethyl alcohol and 2-propanol
B) Ethane and hemi-acetal
C) 2-propanol and acetal
D) Propane and methyl acetate
Correct Answer: C
Solution :
Ethanal with \[C{{H}_{3}}MgBr\] gives propanol-2 (after hydrolysis) and with \[{{C}_{2}}{{H}_{5}}OH\], it gives acetal. \[\underset{\text{Acetaldehyde}}{\mathop{C{{H}_{3}}CHO}}\,+C{{H}_{3}}MgBr\to C{{H}_{3}}CH<\begin{matrix} OMgBr \\ C{{H}_{3}}\ \ \ \, \\ \end{matrix}\xrightarrow{{{H}^{+}}}\]\[\underset{\text{2 propanol}}{\mathop{C{{H}_{3}}CH<\begin{matrix} OH\ \\ C{{H}_{3}} \\ \end{matrix}}}\,\] \[C{{H}_{3}}CHO+2{{C}_{2}}{{H}_{5}}OH\xrightarrow{\text{dry }HCl}\underset{\text{Acetal}}{\mathop{C{{H}_{3}}CH<\begin{matrix} O{{C}_{2}}{{H}_{5}} \\ O{{C}_{2}}{{H}_{5}} \\ \end{matrix}}}\,\]
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