A) Ethylene glycol
B) Ethylene oxide
C) Ethylene dinitrate
D) Ethane
Correct Answer: A
Solution :
\[\underset{\text{Ethylene}}{\mathop{{{H}_{2}}C=C{{H}_{2}}}}\,+\underset{(\text{hypochlorous})}{\mathop{HOCl}}\,\to \underset{\text{Ethylene chlorohydrine}}{\mathop{{{H}_{2}}\underset{Cl\,}{\mathop{\underset{|}{\mathop{C}}\,-}}\,C{{H}_{2}}OH}}\,\]\[\xrightarrow{[NaHC{{O}_{3}}]}\underset{\text{(Ethylene glycol)}}{\mathop{{{H}_{2}}\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,\,-}}\,\underset{OH\ }{\mathop{\underset{|}{\mathop{C}}\,{{H}_{2}}}}\,}}\,+NaCl+C{{O}_{2}}\]
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