A) 9
B) 9/2
C) 2
D) 2/9
Correct Answer: B
Solution :
The equation of lines are \[y-{{y}_{1}}=\frac{m\pm \tan \alpha }{1\mp m\tan \alpha }(x-{{x}_{1}})\] Þ \[y-4=\frac{1\pm \tan 45{}^\circ }{1\mp \tan 45{}^\circ }(x-{{x}_{1}})\] Þ \[y-4=\frac{1\pm 1}{1\mp 1}(x-3)\] Þ \[y=4\] or \[x=3\] Hence, the lines which make the triangle are \[x-y=2,\] \[x=3\] and \[y=4\]. The intersection points of these lines are \[(6,\,4),\,(3,\,1)\] and \[(3,\,4)\] \ \[\Delta =\frac{1}{2}[6(-3)+3(0)+3(3)]\] \[=\frac{9}{2}\].You need to login to perform this action.
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