A) A.P.
B) G.P.
C) H.P.
D) None of these
Correct Answer: C
Solution :
\[\frac{a}{b+c},\frac{b}{c+a},\frac{c}{a+b}\] are in H.P. Its reciprocal is, \[\frac{b+c}{a},\frac{c+a}{b},\frac{a+b}{c}\] are in A.P. Add 1 to each term, we get \[\frac{a+b+c}{a},\frac{a+b+c}{b},\frac{a+b+c}{c}\]\[\Rightarrow \frac{1}{a},\frac{1}{b},\frac{1}{c}\]are in A.P. Þ \[a,\,b,\,c\] are in H.P.
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