A) \[\frac{a+b}{a-b}\]
B) \[\frac{a-b}{a+b}\]
C) \[\frac{a}{a+b}\]
D) None of these
Correct Answer: B
Solution :
\[\tan \frac{A-B}{2}=\frac{a-b}{a+b}\cot \frac{C}{2}=\frac{a-b}{a+b}\tan \left( \frac{A+B}{2} \right)\] Þ \[\tan \frac{A-B}{2}\cot \frac{A+B}{2}=\frac{a-b}{a+b}\].
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