A) \[{{15}^{o}}\]
B) \[{{30}^{o}}\]
C) \[{{45}^{o}}\]
D) None of these
Correct Answer: B
Solution :
We have \[\tan \frac{C-B}{2}=\frac{c-b}{c+b}\cot \frac{A}{2}\] \ \[\tan \left( \frac{C-B}{2} \right)=\frac{\sqrt{3}+1-2}{\sqrt{3}+1+2}\cot {{15}^{o}}=\frac{1}{\sqrt{3}}\] Þ \[\frac{C-B}{2}={{30}^{o}}\].
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