A) \[\frac{\sqrt{3}+1}{3}c{{m}^{2}}\]
B) \[\frac{\sqrt{3}+1}{2}c{{m}^{2}}\]
C) \[\frac{\sqrt{3}+1}{2\sqrt{2}}c{{m}^{2}}\]
D) \[\frac{\sqrt{3}+1}{3\sqrt{2}}c{{m}^{2}}\]
Correct Answer: B
Solution :
\[\Delta =\frac{1}{2}\frac{{{a}^{2}}\sin B\sin C}{\sin (B+C)}=\frac{1}{2}\frac{{{(\sqrt{3}+1)}^{2}}.\frac{1}{2}\times \frac{1}{\sqrt{2}}}{\frac{(\sqrt{3}+1)}{2\sqrt{2}}}=\frac{\sqrt{3}+1}{2}\].
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