A) 2, 2, 3
B) 1, 1, -2
C) - 2, 3, 3
D) -2, -2, 1
Correct Answer: B
Solution :
Given equation is \[{{x}^{3}}-3x+2=0\] Þ \[{{x}^{2}}(x-1)+x(x-1)-2(x-1)=0\] Þ \[(x-1)({{x}^{2}}+x-2)=0\]Þ \[(x-1)(x-1)(x+2)=0\] Hence roots are \[1,1,-2\]You need to login to perform this action.
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