A) \[2n\pi \pm \frac{\pi }{6}\]
B) \[n\pi \pm \frac{\pi }{6}\]
C) \[2n\pi \pm \frac{\pi }{3}\]
D) \[n\pi \pm \frac{\pi }{3}\]
Correct Answer: B
Solution :
\[{{\cos }^{2}}\theta =\frac{3}{4}={{\cos }^{2}}\left( \frac{\pi }{6} \right)\Rightarrow \theta =n\pi \pm \frac{\pi }{6}\].
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