JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    The value of \[\theta \] satisfying the given equation \[\cos \theta +\sqrt{3}\sin \theta \] = 2, is   [MNR 1981; EAMCET 1989]

    A) \[\frac{\pi }{3}\]

    B) \[\frac{5\pi }{3}\]

    C) \[\frac{2\pi }{3}\]

    D) \[\frac{4\pi }{3}\]

    Correct Answer: A

    Solution :

    \[\sin \left( \theta +\frac{\pi }{6} \right)=1=\sin \left( \frac{\pi }{2} \right)\Rightarrow \theta =\frac{\pi }{2}-\frac{\pi }{6}=\frac{\pi }{3}\].


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