A) \[b\cot \theta \]
B) \[b\]
C) \[b\tan \theta \]
D) \[b\sqrt{2}\]
Correct Answer: B
Solution :
Distance\[=\sqrt{{{b}^{2}}{{\cos }^{2}}\theta +{{b}^{2}}{{\sin }^{2}}\theta }=b\].You need to login to perform this action.
You will be redirected in
3 sec