A) 1
B) \[\frac{1}{\sqrt{3}}\]
C) \[\sqrt{3}\]
D) \[\frac{1}{2}\]
Correct Answer: C
Solution :
\[\frac{\sin \,\,{{70}^{o}}+\cos \,\,{{40}^{o}}}{\cos \,\,{{70}^{o}}+\sin \,\,{{40}^{o}}}\] \[=\frac{\sin 70{}^\circ +\sin 50{}^\circ }{\sin 20{}^\circ +\sin 40{}^\circ }=\frac{2\sin 60{}^\circ \cos 10{}^\circ }{2\sin 30{}^\circ \cos (-10{}^\circ )}\] \[=\frac{\sin \,\,{{60}^{o}}}{\sin \,\,{{30}^{o}}}=\frac{\sqrt{3}}{2}.\frac{2}{1}=\sqrt{3}\].
You need to login to perform this action.
You will be redirected in
3 sec
