10th Class Mathematics Introduction to Trigonometry Question Bank Trigonometry

  • question_answer
    Find the value of \[x\] from the equation \[x\sin \frac{\pi }{6}{{\cos }^{2}}\frac{\pi }{4}=\frac{{{\cot }^{2}}\frac{\pi }{6}\sec \frac{\pi }{3}\tan \frac{\pi }{4}}{{{\operatorname{cosec}}^{2}}\frac{\pi }{4}\operatorname{cosec}\frac{\pi }{6}}\]

    A) 4

    B) 6

    C) -2

    D) 0

    Correct Answer: B

    Solution :

     \[x\sin \frac{\pi }{6}{{\cos }^{2}}\frac{\pi }{4}=\frac{{{\cot }^{2}}\frac{\pi }{6}\sec \frac{\pi }{3}\tan \frac{\pi }{4}}{\text{cose}{{\text{c}}^{2}}\frac{\pi }{4}\text{cosec}\frac{\pi }{6}}\] or            \[x\times \frac{1}{2}\times \frac{1}{2}=\frac{{{\left( \sqrt{3} \right)}^{2}}\times 2\times 1}{{{\left( \sqrt{2} \right)}^{2}}\times 2}\] or            \[x\times \frac{1}{4}=\frac{3\times 2\times 1}{2\times 2}=\frac{3}{2}=\frac{1}{2}\] or            \[x=6\]


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