10th Class Mathematics Introduction to Trigonometry Question Bank Trigonometry

  • question_answer
    In a triangle \[ABC,\,\,\tan A+\tan B+\tan C\] is equal to

    A) \[1\]

    B) \[0\]

    C) \[\tan A\,\,\tan B\,\,\tan C\]

    D) \[-1\]

    Correct Answer: C

    Solution :

     Since A, B and C are the angles of a triangle \[\therefore \]  \[A+B+C=\pi \] \[\therefore \]  \[\tan (A+B+C)=\tan \pi =0\] or \[\frac{\tan A+\tan B+\tan C-\tan A\tan B\tan C}{1-\tan A\tan B-\tan B\tan C-\tan C\tan A}=0\] or \[\tan A+\tan B+\tan C=\tan A.\,\tan \,B.\,tanC\]


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