A) 0.036
B) 0.36
C) 3.6
D) 36
Correct Answer: C
Solution :
\[{{n}_{2}}={{n}_{1}}{{\left( \frac{{{M}_{1}}}{{{M}_{2}}} \right)}^{1}}{{\left( \frac{{{L}_{1}}}{{{L}_{2}}} \right)}^{1}}{{\left( \frac{T}{{{T}_{2}}} \right)}^{-2}}\] = \[100{{\left( \frac{gm}{kg} \right)}^{1}}{{\left( \frac{cm}{m} \right)}^{1}}{{\left( \frac{\sec }{min} \right)}^{-2}}\] = \[100{{\left( \frac{gm}{{{10}^{3}}gm} \right)}^{1}}{{\left( \frac{cm}{{{10}^{2}}cm} \right)}^{1}}{{\left( \frac{\sec }{60\sec } \right)}^{-2}}\] n2 = \[\frac{3600}{{{10}^{3}}}=3.6\]
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