A) 2
B) 1
C) 3
D) 4
Correct Answer: A
Solution :
\[N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O\to \ 2NaOH+{{H}_{2}}C{{O}_{3}}\]and \[2NaOH\]\[2N{{a}^{+}}+2O{{H}^{-}}\] Hence, it is clear that \[2O{{H}^{-}}\] ions will be formed on hydrolysis of one molecule of sodium corbonate.
You need to login to perform this action.
You will be redirected in
3 sec
