A) \[AgN{{O}_{3}}\] and \[KBr\]
B) \[BaC{{O}_{3}}\] and \[ZnS\]
C) \[FeC{{l}_{3}}\] and \[CaC{{O}_{3}}\]
D) \[Mn{{(N{{O}_{3}})}_{2}}\] and \[MgS{{O}_{4}}\]
Correct Answer: B
Solution :
\[BaC{{O}_{3}}+2HCl\to BaC{{l}_{2}}+{{H}_{2}}O+C{{O}_{2}}\] \[ZnS+2\underset{\text{(dil}\text{.)}}{\mathop{HCl}}\,\to ZnC{{l}_{2}}+{{H}_{2}}S\]
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