A) \[CrO_{4}^{2-}\]
B) \[PO_{4}^{3-}\]
C) \[MnO_{4}^{-}\]
D) \[NH_{4}^{+}\]
Correct Answer: D
Solution :
Nessler?s reagent gives red precipitate with \[NH_{4}^{+}\] \[N{{H}_{4}}Cl+2{{K}_{2}}[Hg{{I}_{4}}]+4KOH\to \]\[\underset{\text{Iodide of Millon }\!\!'\!\!\text{ s base (Brown ppt)}}{\mathop{N{{H}_{2}}-Hg-O-Hg-I}}\,+\ 7KI\ +\ KCl\ +\ 3{{H}_{2}}O\]
You need to login to perform this action.
You will be redirected in
3 sec
