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NEET AIPMT SOLVED PAPER MAINS 2012

  • question_answer
    Given the reaction between two gases represented by \[{{A}_{2}}\] and \[{{B}_{2}}\] to give the compound AB(g).\[{{A}_{2}}(g)+{{B}_{2}}(g)2AB(g)\] At equilibrium, the concentration of \[{{A}_{2}}=3.0\times {{10}^{-3}}M\] of\[{{B}_{2}}=4.2\times {{10}^{-3}}M\] of\[AB=2.8\times {{10}^{-3}}M\]If the reaction \[{{527}^{o}}C\]takes place in a sealed vessel at\[{{527}^{o}}C\], then the value of K, will be

    A)  2.0                        

    B)  1.9                        

    C)  0.62                      

    D)  4.5

    Correct Answer: C

    Solution :

    \[{{A}_{2}}(g)+{{B}_{2}}2AB(g)\]The equilibrium constant is given by            \[{{K}_{c}}=\frac{{{[AB]}^{2}}}{[{{A}_{2}}][{{B}_{2}}]}=\frac{{{(2.8\times {{10}^{-3}})}^{2}}}{(3.0\times {{10}^{-3}})(4.2\times {{10}^{-3}})}\]                                 \[=\frac{7.84}{12.6}\]                                 \[=0.62\]


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