A) 3.2 sec
B) 1.6 sec
C) 6.4 sec
D) 1.2 sec
Correct Answer: B
Solution :
: \[V=3\hat{i}+8\hat{j}\] \[\therefore \]\[{{V}_{x}}=V\cos \theta =3=\]horizontal velocity \[{{V}_{y}}=V\sin \theta =8=\]vertical velocity Time of flight of projectile\[=2t\] where\[t=\]time during which\[{{v}_{y}}\]becomes zero \[\therefore \]Final velocity\[(v)=\]Initial velocity\[(u)-gt\]. Or \[0={{V}_{y}}-gt\] or \[t=\frac{{{V}_{y}}}{g}=\frac{8}{10}=0.8\,\sec \] \[\therefore \]Time of flight\[=(2t)=1.6\text{ }sec\].
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