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AMU Medical AMU Solved Paper-1996

  • question_answer
    For three different metals A,B,C photoemission is observed one by one. The graphs of maximum kinetic energy\[({{K}_{\max }})vs\]frequency of incident radiation (i)) are sketched as
    (I)
    (II)
    (III)
    (IV)
    Which one of these represents the correct situation?

    A)  I                  

    B)  II

    C)  III                

    D)  IV

    Correct Answer: A

    Solution :

    : For photoelectric effect, \[h\upsilon =\phi +\]kinetic energy of electron emitted \[h\upsilon ={{K}_{\max }}\]for maximum kinetic energy or   \[\frac{{{K}_{\max }}}{\upsilon }=h=\]slope of the graph. = it is a constant. Frequency\[\upsilon \]of incident light is positive. Hence figure\[(I)\]represents the graph.


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