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BCECE Engineering BCECE Engineering Solved Paper-2001

  • question_answer
    The focal length of lens is 5 cm. If die least distance of distinct vision is 25 cm the magnification is:

    A)  2.1                                        

    B)  1                                            

    C)  1.1                        

    D)         6

    Correct Answer: D

    Solution :

    The magnification of a simple microscope, when virtual image is formed at least distance of distinct vision (D) is given by \[M=1+\frac{D}{f}\] Given, \[f=5cm,\,D=25\,cm\] \[\therefore \]  \[M=1+\frac{25}{5}=1+5=6\]


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