BCECE Engineering BCECE Engineering Solved Paper-2001

  • question_answer
    The specific resistance of wire of length 1 m, area .of cross-section \[0.5\,{{m}^{2}}\] is \[25\,\mu \Omega \,m\]. The resistance of the wire will be:

    A)  \[5\times {{10}^{-5}}\,\Omega \]

    B)  \[3\times {{10}^{-6}}\,\Omega \]

    C)  \[46\times {{10}^{6}}\,\Omega \]

    D)  \[2\times {{10}^{6}}\,\Omega \]

    Correct Answer: A

    Solution :

    Resistance R of a given conductor, at a constant temperature, is directly proportional to its length and inversely proportional to its area of cross-section A. i.e.,     \[R\propto \frac{l}{A}\]or \[R=\rho \frac{l}{A}\] where \[\rho \]is called the specific resistance of  the material. Given, \[\rho =25\times {{10}^{-6}}\Omega m,\,l=1\,m,\,\,A=0.5\,{{m}^{2}}\] \[\therefore \]  \[R=\frac{25\times {{10}^{-6}}\times 1}{0.5}\]                 \[=50\times {{10}^{-6}}\] \[=5\times {{10}^{-5}}\Omega \]


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