BCECE Engineering BCECE Engineering Solved Paper-2005

  • question_answer
    The radius of solid metallic non-conducting sphere is 60 cm and charge on the sphere is \[500\,\mu C\]. The electric field at a distance 10 cm from centre of sphere is:

    A)  \[2\times {{10}^{6}}\,N/C\]       

    B)                         \[2\times {{10}^{8}}\,N/C\]

    C)         \[5\times {{10}^{6}}\,N/C\]                       

    D)         \[5\times {{10}^{8}}\,N/C\]

    Correct Answer: A

    Solution :

    The point 10 cm from centre of sphere will be inside the sphere. Hence, \[{{E}_{inside}}=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{qr}{{{R}^{3}}}\]e Here, \[q=500\times {{10}^{-6}}C,\,r=10\,cm\,=0.1\,m\] \[R=60\,cm=0.60\,m\] \[\therefore \]  \[{{E}_{inside}}=(9.0\times {{10}^{9}})\times \frac{500\times {{10}^{-6}}\times 0.1}{{{(0.60)}^{3}}}\] \[=2\times {{10}^{6}}\,N/C\]


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