BCECE Engineering BCECE Engineering Solved Paper-2008

  • question_answer
    The volume of water to be added to 100 cm3 of \[0.5\text{ }N\text{ }{{H}_{2}}S{{O}_{4}}\]to get decinormal concentration is

    A) \[400\,c{{m}^{3}}\]       

    B)        \[450\,c{{m}^{3}}\]        

    C)        \[~500\,c{{m}^{3}}\]       

    D)        \[100\,c{{m}^{3}}\]

    Correct Answer: A

    Solution :

    \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[0.5\times 100=0.1\times {{V}_{2}}\] \[{{V}_{2}}=500\,c{{m}^{2}}\] \[\therefore \]Water to be added to \[100\,c{{m}^{3}}\]solution                                 \[=500-100=400\,c{{m}^{3}}\]


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