BCECE Engineering BCECE Engineering Solved Paper-2012

  • question_answer
    \[{{\,}_{92}}{{U}^{235}}\]nucleus absorbs a neutron and disintegrate in \[{{\,}_{54}}X{{e}^{139}},{{\,}_{38}}S{{r}^{139}}\] and X so, what will be product X?

    A)  3-neutrons     

    B)         2-neutrons       

    C)         \[\alpha \]-particle       

    D)         \[\beta \]-particle

    Correct Answer: A

    Solution :

    \[{{\,}_{\text{92}}}{{\text{U}}^{\text{235}}}\] nucleus absorbs a neutron and then disintegrate into \[{{\,}_{54}}X{{e}^{139}},{{\,}_{38}}S{{r}^{94}}\] and X. Thus, \[{{\,}_{92}}{{U}^{235}}+{{\,}_{0}}{{n}^{1}}\xrightarrow{{}}{{\,}_{54}}X{{e}^{139}}\] \[+{{\,}_{38}}S{{r}^{94}}+\underset{x}{\mathop{{{3}_{0}}{{n}^{1}}}}\,\]


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