BCECE Engineering BCECE Engineering Solved Paper-2012

  • question_answer
    \[\text{CuS}{{\text{O}}_{\text{4}}}\]when reacts with KCN forms CuCN which is insoluble in water. It is soluble in excess of KCN due to the formation of the following complex

    A)  \[{{\text{K}}_{2}}[Cu{{(CN)}_{4}}]\]

    B)         \[{{K}_{3}}[Cu{{(CN)}_{4}}]\]

    C)         \[CuC{{N}_{2}}\]            

    D)         \[Cu[K\,Cu{{(CN)}_{4}}]\]

    Correct Answer: B

    Solution :

    \[\text{CuS}{{\text{O}}_{\text{4}}}\]reacts with KCN and gives a white precipitate of cuprous cyanide and cyanogen gas. The cuprous cyanide dissolves in excess of KCN forming \[{{\text{K}}_{3}}[Cu{{(CN)}_{4}}].\] \[CuS{{O}_{4}}+2KCN\xrightarrow{{}}{{K}_{2}}S{{O}_{4}}+Cu{{(CN)}_{2}}\] \[2Cu{{(CN)}_{2}}\xrightarrow{{}}\underset{\text{insoluble}}{\mathop{2CuCN}}\,+\underset{\text{cyanogen}}{\mathop{CN-CN}}\,\] \[CuCN+3KCN\xrightarrow{{}}\underset{\text{soluble}}{\mathop{{{K}_{2}}[Cu(C{{N}_{4}})]}}\,\]


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