BCECE Medical BCECE Medical Solved Papers-2004

  • question_answer
    Water falls from a height 500 m. The rise in temperature of water at bottom if whole of the energy remains in water, will be : (specific heat of water is c = 4.2 kJ/kg)

    A)  \[{{0.23}^{o}}C\]

    B)  \[{{1.16}^{o}}C\]

    C)  \[{{0.96}^{o}}C\]

    D)  \[{{1.02}^{o}}C\]

    Correct Answer: B

    Solution :

    Key Idea: Potential energy = increase in heat of water. From law of conservation of energy, we know that energy can neither be created nor destroyed, it remains conserved. When water falls from a height, it has potential energy\[(mgh)\], this is used in heating up the water\[(mc\Delta \theta )\]. Hence, we have                 \[mgh=mc\Delta \theta \] \[\Rightarrow \] \[\Delta \theta =\frac{gh}{c}\] \[=\frac{9.8\times 500}{4.2\times {{10}^{3}}}={{1.16}^{o}}C\]


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