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BCECE Medical BCECE Medical Solved Papers-2010

  • question_answer
    Nitrogen \[({{N}_{2}})\] is in equilibrium state at T = 421 K. The value of most probable speed, \[{{v}_{mp}}\] is

    A)  400 m/s       

    B)  421 m/s

    C)  500 m/s       

    D)  600 m/s

    Correct Answer: C

    Solution :

    Most probable velocity,                 \[{{v}_{mp}}=\sqrt{\frac{2kT}{m}}\]                 \[=\sqrt{\frac{2RT}{m}}=\sqrt{\frac{8.31\times 421}{28\times {{10}^{-3}}}}\] = 499.89 = 500 m/s


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