A) 1, 4-dicarboxy-2, 3-dihydroxyethane
B) \[\alpha ,\,\,\alpha \]-dihydroxybutane-1, 4-dioic acid
C) 1, 4-dihydroxybutane-2, 3-dioic acid
D) 2, 3-dihydroxybutane-1, 4-dioic acid
Correct Answer: D
Solution :
Tartaric acid is \[HO-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{{{\underset{\begin{smallmatrix} | \\ HO-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{{{C}^{3}}}}\,-\underset{4}{\mathop{C}}\,OOH \end{smallmatrix}}{\mathop{C}}\,}^{2}}}}\,-\overset{1}{\mathop{C}}\,OOH\] 2, 3-dihydroxybutane-1, 4-dioic acid.
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