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  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    A bar magnet of magnetic M is cut into two parts of equal length. The magnetic moment of each part will be

    A)  12M                                     

    B)  M

    C)  0.5M                                    

    D)  zero

    Correct Answer: C

    Solution :

    Magnetic moment\[~=M.\] Also from the formula we have magnetic moment \[M=\text{pole}\,\text{strength}\,\,\text{ }\!\!\times\!\!\text{ }\,\,\text{length}\] Since, the pole strength of each part remains the same and it becomes half, therefore, magnetic moment of each part will be \[\frac{M}{2}=0.5\,M\]


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