CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2004

  • question_answer
    A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is \[340\,m{{s}^{-1}}\], the distance between the cliffs is:

    A)  680 m                                  

    B)  1700 m

    C)  340 m                                  

    D)  1620 m

    Correct Answer: C

    Solution :

    Let the distance between the two cliffs be d. Since, the man is standing midway between the two cliffs, then the distance of man from either end is \[d/2\]. The distance travelled by sound (in producing an echo)                 \[2\times \frac{d}{2}=\upsilon \times t\] \[\Rightarrow \]                               \[d=340\times 1=340\,m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner